/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public int countNodes(TreeNode root) {
        if (root == null)
            return 0;
        
        return countNodes(root.left) + countNodes(root.right) + 1;
    }
}
This solution is O(n) in number of nodes in the binary tree and is a generic solution that can be used to solve any binary tree for that matter.
The fact that this is a complete binary tree, brings to my mind another solution approach with O((lg n)^2) solution which I'll share here very soon!
Until next time,
Stay Tuned and Happy Coding!
See ya later!!
 
 
 
 
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