/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
public int countNodes(TreeNode root) {
if (root == null)
return 0;
return countNodes(root.left) + countNodes(root.right) + 1;
}
}
This solution is O(n) in number of nodes in the binary tree and is a generic solution that can be used to solve any binary tree for that matter.
The fact that this is a complete binary tree, brings to my mind another solution approach with O((lg n)^2) solution which I'll share here very soon!
Until next time,
Stay Tuned and Happy Coding!
See ya later!!
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