Here's my recursive solution of the same:
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */ class Solution { public boolean isSameTree(TreeNode p, TreeNode q) { if (p == null) { if (q == null) return true; return false; } else { if (q == null) return false; } if (p.val != q.val) return false; boolean sameTree = true; sameTree = isSameTree(p.left, q.left); if (sameTree) sameTree = isSameTree(p.right, q.right); return sameTree; } }
Sweet and Simple!
Happy Coding!!
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